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1000x^2-1000=0
a = 1000; b = 0; c = -1000;
Δ = b2-4ac
Δ = 02-4·1000·(-1000)
Δ = 4000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4000000}=2000$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2000}{2*1000}=\frac{-2000}{2000} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2000}{2*1000}=\frac{2000}{2000} =1 $
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